Given that there are three 'dice' or number combinations and we know that one of those factors is roughly half of the other two. We can extrapolate the actual or total different combinations that are available to us.
Dice 1 has a range of 0 - 9
Dice 2 has a range of 0 - 5
Dice 3 has a range of 0 - 9
The likely combination total comes out to 10 * 6 * 10 = 600 (This is a very rough calculation but probably close to the actual number.)
So if someone is lucky enough to guess the actual combination in around 100 guesses then they are doing very well. There is also a probability factor and an overall percentage of that factor as well. But I'm at work and I don't have access to my statistics book to provide you with that data.
The number combinations are quite extensive. Starting with 0-0-0 it would look something like this:
0-0-0, 0-0-1, 0-0-2, 0-0-3, 0-0-3, 0-0-4, 0-0-5, 0-0-6, 0-0-7, 0-0-8, 0-0-9, 0-1-0, 0-1-1, 0-1-2, 0-1-3, 0-1-4, 0-1-5, 0-1-6, 0-1-7, 0-1-8, 0-1-9, 0-2-0, 0-2-1, 0-2-2, 0-2-3, 0-2-4, 0-2-5, 0-2-6, 0-2-7, etc....
As you can see the number combination will rapidly pass through the 100 combination threshold and continue on well into the hundreds.
But what do I know!
![Wave :wave: :wave:](https://www.findmall.com/styles/smileys/mf_wave.gif)