I was not going to respond further, but since you want to chase me around the Internet... ;-)
I'm attempting to get clarification from Carl on the Whites forum. I'm a retired electronics engineer, and understand fairly well how metal detectors work, circuitwise.
I know what Carl wrote, but his explanation, was not technical and misleading from an electronics perspective. What does "hit harder" mean, and why? Also, if you'd watched the video I referred to, the detail was there, but was not obvious, While Mark made a sweeping statement about low frequency was better for high conductors and vise-versa, he did not clarify it. The detail was in the VDI wheel and how frequency relates to it - and the discrimination circuitry (which really wasn't mentioned).
Note Mark said 1) The length of the arrows represent intensity. 2) the higher the frequency, the more target arrows point to the right, towards the +95 axis (all metals higher intensity). However, this crams all the high VDI numbers together, towards the +95 axis, which is real close to the -95 axis coming up from the bottom. If your ground balance is near -95 (near +95 on the wheel), then you lose sensitivity to the +95 signals due to the "wrap around" of the circuitry. Another way of putting it - your discrimination has only a couple of VDI numbers to work with. An analogy would be setting discrimination to +24, when nickels are +26 - you would then lose sensitivity to nickels due to the lesser ability of the circuitry to differentiate between the two. That is why you normally set your discrimination to JUST reject nails not further. This is the real reason silver coins are "hit harder" with the low frequencies - due to the discrimination circuitry, not the frequency itself. Does this make sense?
George